If x=at^{2}, y= 2at , then find dy/dx.

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#### Solution

We have, `y = 2at `

`dy/dt=2ad/dt(t)=2a(1)=2a`

also `x=at^2`

`dx/dx=a d/dt(t^2)=a(2t)=2at`

now `dy/dx= (dy/dt)/(dx/dt)=(2a)/(2at)=1/t`

Concept: Derivatives of Functions in Parametric Forms

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